A mixture of oxygen and hydrogen gases at 1.5 bar pressure contains 30% by weight of hydrogen. Calculate the partial pressure(bar) of hydrogen gas.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 1.31.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
wt. of H2=30g; mol. wt. of H2=2gmol−∴ no. of mol of H2= wt. / mol. wt. =30/2=15mol. wt. of O2=100−30=70g; mol. wt. of O2=2×16=32gmol−∴ no. of mol of O2= wt. / mol. wt. =70/32=2.1875molTotal no. of mol =15+2.1875=17.1875mol∴ Partial pressure of H2=nH2 Total no. of mol×Total pressure=1517.1875×1.5=1.31bar