Mixture of volatile components A and B has total vapour pressure (in Torr) p=254−119 xA , where xA is mole fraction of A in mixture. Hence pA∘ and p B∘are (in Torr)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
254, 119
b
119, 254
c
135, 254
d
119, 373
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Ptotal =P∘ A XA+P∘B(1−XA)PT=P∘B−XAP∘B−P∘A=254−XA119P∘B=254⇒P∘B−P∘A=119⇒254−119=P∘A∴P∘A=135