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Q.

A mixture of weak acid is 0.1 M in HCOOH (Ka = 1.8x 10-4) and 0.1 M in HOCN (Ka= 3.1x 10-4). Hence [H3O+] is

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a

7.14×10−3M

b

4.1×10−4M

c

0.20 M

d

4.1×10−3M

answer is A.

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Detailed Solution

H3O+=K1C1+K2C2 =1.8×10−4×0.1+3.1×10−4×0.1 =7×10−3M
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