A, mixture x containing $$0.02$$ mol of $$CoNH35SO4Br$$ and $$0.02$$ mol of $$CoNH35BrSO4$$ was prepared in $$2$$ L of $$solution.1$$ L of mixture $$X+excess$$ $$AgNO3$$ → $$Y1$$ L of mixture $$X+excess$$ $$BaCl2$$ → ZThe number of moles of Y and Z are

Question

A, mixture x containing $$0.02$$ mol of $$CoNH35SO4Br$$  and  $$0.02$$ mol  of  $$CoNH35BrSO4$$ was prepared in $$2$$ L of $$solution.1$$  L  of  mixture  $$X+excess$$  $$AgNO3$$ →  $$Y1$$  L  of  mixture  $$X+excess$$  $$BaCl2$$ →  ZThe number of moles of Y and Z are

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A mixture X containing $$0.02$$ mol of $$CoNH35SO4Br$$  and  $$0.02$$ mol  of  $$CoNH35BrSO4$$ was prepared in $$2$$ L of solution. This means $$1$$ L of the mixture contains $$0.01$$ mol of $$CoNH35SO4Br$$  $$0.01$$ mol  of  $$CoNH35BrSO41$$  L  of  mixture  $$X+excess$$  $$AgNO3$$ →  $$0.01$$ mol  $$AgBr1$$  L  of  mixture  $$X+excess$$  $$BaCl2$$ →  $$0.01$$  mol  $$BaSO4This$$ is according to the following reactions taking place :$$CoNH35SO4Br$$  $$+$$  $$AgNO3$$ →  $$CoNH35SO4$$ $$NO3+AgBr$$↓$$CoNH35BrSO4$$  $$+$$  $$BaCl2$$ →  $$CoNH35Br$$ $$Cl2+BaSO4$$↓

A, mixture x containing 0.02 mol of CoNH35SO4Br and 0.02 mol of CoNH35BrSO4 was prepared in 2 L of solution.1 L of mixture X+excess AgNO3 → Y1 L of mixture X+excess BaCl2 → ZThe number of moles of Y and Z are

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