A, mixture x containing 0.02 mol of CoNH35SO4Br  and  0.02 mol  of  CoNH35BrSO4 was prepared in 2 L of solution.1  L  of  mixture  X+excess  AgNO3 →  Y1  L  of  mixture  X+excess  BaCl2 →  ZThe number of moles of Y and Z are

A mixture X containing 0.02 mol of CoNH35SO4Br  and  0.02 mol  of  CoNH35BrSO4 was prepared in 2 L of solution. This means 1 L of the mixture contains 0.01 mol of CoNH35SO4Br  0.01 mol  of  CoNH35BrSO41  L  of  mixture  X+excess  AgNO3 →  0.01 mol  AgBr1  L  of  mixture  X+excess  BaCl2 →  0.01  mol  BaSO4This is according to the following reactions taking place :CoNH35SO4Br  +  AgNO3 →  CoNH35SO4 NO3+AgBr↓CoNH35BrSO4  +  BaCl2 →  CoNH35Br Cl2+BaSO4↓