Q.

Mixture X = 0.02 mol of CoNH35SO4 and 0.02 mol of CoNH35BrSO4 was prepared in 2 litre of solution 1 litre of mixture X + excess AgNO3→Y1 litre of mixture X + excess BaCl2→ZNumber of moles of Y and Z are

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a

0.01, 0.01

b

0.02, 0.01

c

0.01, 0.02

d

0.02, 0.02

answer is A.

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Detailed Solution

CoNH35SO40.02 moleBr+AgNO3→CoNH35.SO40.02 mole YNO3+AgBrCoNH35Br20.02 moleSO4+BaCl2→CoNH35Br0.02 mole ZCl2+BaSO4On using 1 L solution, we will get 0.01 mole Y and 0.01 mole Z.
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Mixture X = 0.02 mol of CoNH35SO4 and 0.02 mol of CoNH35BrSO4 was prepared in 2 litre of solution 1 litre of mixture X + excess AgNO3→Y1 litre of mixture X + excess BaCl2→ZNumber of moles of Y and Z are