Mixture X = 0.02 mole of Co(NH3)5SO4Br and 0.02 mole of Co(NH3)5BrSO4 was prepared in 2 L of solution.        1 L of mixture of X + excess AgNO3→ Y        1 L of mixture X+ excess BaCl2→ Z        Sum of number of moles of Y and Z are

0.02 moles of Co(NH3)5BrSO4 and 0.02 moles of Co(NH3)5SO4Br  was prepared in two liters of solution. So, the concentration of them in solution is 0.01 mol/L and 0.01 mol/L respectively (possess the same gram molecular weight as they are isomers).During the reaction with AgNO3 (excess) to X, AgBr is precipitated as follows:CoNH35SO4Br+AgNO3→CoNH35SO4NO3+AgBr(0.01 mole)Hence, number of moles of Y = 0.01 In addition to excess BaCl2 to X, SO4-2 ion of Co(NH3)5BrSO4 is precipitated in form of Z.[Co(NH3)5Br]SO4+BaCl2→     BaSO4↓+[Co(NH3)5Br]Cl2 0.01 mol/L            (excess)        0.01mol/L (Z)      soluble Hence, the number of moles of Z = 0.01 Thus, the number of moles of Y and Z are 0.01 and 0.01 respectively