2.5 mL of Agl. Ag+ sol is coagulated by 15 mL of 0.001 M KI , What is flocculation value of KI?

[AgI]Ag++I−⟶AgI↓+AgI↓15 mL of 0.001 M KI = 15 x 0.001 millimoles                                      required by 2.5 mL of KI∴1000mL of [AgI]Ag+require =15×0.0012.5×1000 millimoles of KI= 6 millimoles per L