100 mL of an aqueous solution contains 10 g of a dibasic acid (Mol. wt = 100). If the density of the solution is 1.5 g /cc, then the mole fraction of the solute is :

Moles of dibasic acid 10100=0.10molwt. of sol = vol x density = 100 × 1.5 = 150 gwt. of water = 150 – 10 = 140 gmoles of water =14018=7.8 mole x1=0.100.10+7.8=0.107.9=0.013