100 mL of a buffer solution contains 0.1 M each of weak acid HA and salt NaA. How many gram of NaOH should be added to the buffer so that it pH will be 6?(Ka of HA = 10-5)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 0.328.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For acidic buffer, pH=pKa+log⁡0.10.1pH=pKa=−log⁡10−5=5Rule: ABA (In acidic buffer (A), on addition of SB (B), the concentration of WA(A) decreases and that of salt increases.Let x M of NaOH is added.pHnew =5+log⁡0.1+x0.1−x6−5=log⁡0.1+x0.1−x0.1+x0.1−x= Antilog (1)=10Solve for x:x=0.082M=0.0821000×100=0.0082mol(100mL)−1=0.0082×40g(100mL)−1=0.328g

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th