Q.

30 mL of CH3OH (d = 0.8 g/cm3) is mixed with 60 mL of C2H5OH (d = 0.92 g/cm3) at 25°C to form a solution of density 0.88 g/cm3. Select the correct option(s) :

Difficult

Unlock the Full Solution and Master the Concept

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept

By Expert Faculty of Sri Chaitanya

Molarity and molality of resulting solution are 6.33 M and 13.59 m respectively.

The mole fraction of solute and molality are 0.38 and 13.59 m respectively.

Molarity and percentage change in volume are 13.5 M and zero respectively.

Mole fraction of solvent and molality are 0.62 and 13.59 m respectively.

answer is 2,4.

(Detailed Solution Below)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

30 mL of CH3OH ............CH3OH is solute (less amount)Mass of CH3OH = 30 × 0.8 = 24 gMass of C2H5OH = 60 × 0.92 = 55.2 gMass of solution = 79.2 g Volume of solution =79.20.88=90mL Molarity =nCH0OV(L)=24/3290×1000=8.33M Molality =24/3255.2×1000=13.59m Mole fraction of solute =24322432+55.246=0.38 Mole fraction of solvent =1−0.38=0.62

Choose your Grade and Exam

Connect with our

Expert Counsellors

access to India's best teachers with a record of producing top rankers year on year.

+91

We will send a verification code via OTP.