30 mL of CH3OH (d = 0.8 g/cm3) is mixed with 60 mL of C2H5OH (d = 0.92 g/cm3) at 25°C to form a solution of density 0.88 g/cm3. Select the correct option(s) :

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Molarity and molality of resulting solution are 6.33 M and 13.59 m respectively.

The mole fraction of solute and molality are 0.38 and 13.59 m respectively.

Molarity and percentage change in volume are 13.5 M and zero respectively.

Mole fraction of solvent and molality are 0.62 and 13.59 m respectively.

answer is B.

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Detailed Solution

30 mL of CH3OH ............CH3OH is solute (less amount)Mass of CH3OH = 30 × 0.8 = 24 gMass of C2H5OH = 60 × 0.92 = 55.2 gMass of solution = 79.2 g Volume of solution =79.20.88=90mL Molarity =nCH0OV(L)=24/3290×1000=8.33M Molality =24/3255.2×1000=13.59m Mole fraction of solute =24322432+55.246=0.38 Mole fraction of solvent =1−0.38=0.62

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