100 ml of ethyl alcohol [d = 0.92 g/ml] and 900 ml of water [d = 1 g/ml] are mixed to form 1 lit solution. The Molarity and molality of the resulting solution are

C2H5OH (solute)                             H2O(solvent)Vs = 100ml                                      Vo =900mlds = 0.92g/cc                                   do = 1g/ccWs = 100(0.92) =92g                       Wo = 900(1) =900gGMW=46 g                                       GMW = 18g