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20 ml of ethyne requires …… ml of air at STP for complete combustion. 

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By Expert Faculty of Sri Chaitanya
a
50 ml
b
25 ml
c
238 ml
d
192 ml
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detailed solution

Correct option is C

C2H2g + 52O2g → 2CO2g + H2Ol ; 20ml          50ml           Volume of oxygen required=50ml; Air contains 21% by volume of oxygen ; Volume of air required=10021×50=238 ml ;


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KMnO4 reacts with oxalic acid according to the equation,

2MnO4-+5C2O42-+16H+2Mn2++10CO2+8H2O

Here, 20 mLof 0.1 M KMnO4 is equivalent to

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