10 ml of FeC2O4 solution requires 30 ml of 0.4 M KMnO4 solution in acidic medium for titration. 25 ml of the same FeC2O4 solution is mixed in some water to make a solution containing 900g of water. Which of the following is/are true for this solution?Kf for water =1.8/Kkg/mol )

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Freezing point of the solution is 0.2 K

The RLVP of the solution is approximately 2×10−3

Osmotic pressure of the initial FeC2O4 solution is 49.2 atm at 300 K

Osmotic pressure of the initial KMnO4 solution (without acid) is 19.68 atm at 300 K

answer is A.

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Detailed Solution

FeC2O4+KMnO4→ Mn2++Fe3++CO2⇒ 10 ×3×M=30×0.4×5M=2⇒π=2×0.82×300×2=49.2 atm ×2=98.4 atmπKMnO4=0.4×0.082×300×2=19.68 atmIn the new FeC2O4 solution nFeC2O4=251000×2=120RLVP=120×2120×2+90018=110110+50=1500andΔT1=1.8×1200.9×2=2×1.8×118=0.2KTf=−0.2K

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