1000 mL of a gas collected at STP which occupies the volume at 2 bar pressure and 127°C. The volume of gas at STP is

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2×273400

400×2273 L

4002×273 L

400×2×273 L

answer is A.

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Detailed Solution

V1=1000 mL=1 L,p1=2barT1=(127+273)K=400 KV2=?,p2=1bar,T2=273 KAccording to combined gas law, p1V1T1=p2V2T2⇒V2=p1V1T2T1p2=2×1×273400×1 L=2×273400 L

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