First slide

Compounds of hydrogen

Question

10 mL of H₂O₂ solution (volume strength - x) requires 10 mL of $\frac{N}{0.56} {MnO}_{4}^{⊝}$ solution in acidic medium. Hence x is

Moderate

A

0.5
B

5.6
C

0.1
D

10

Solution

$N of H_{2} O_{2} = Volume strength / 5 .6 = x / 5 .6$
$mEq. of H_{2} O_{2} \equiv mEq . of {MnO}_{4}^{⊝}$
$∴ N_{1} V_{1} \equiv N_{2} V_{2}$
$\frac{x}{5.6} \times 10 mL \equiv \frac{1}{0.56} \times 10 mL$
$∴ x =^{'} 10' volume strength$

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