25 ml H2O2 on treatment with excess of acidified KI solution liberates iodine. Liberated iodine require 20 ml of 0.3 N Na2S2O3 solution. Calculate volume strength of H2O2 solution
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answer is 1.3.
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Detailed Solution
N1V1H2O2=N2V2Na2S2O3 N1x25=0.3x20N1=0.24V.S of H2O2=Nx5.6= 0.24 × 5.6 = 1.3