25 mL of HCl solution is titrated with 0.10 mole L–1 NaOH solution in a conductivity cell. The data obtained were plotted to give the graph shown belowThe concentration of HCl solution is
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a
0.040 M
b
0.060 M
c
0.080 M
d
0.01 M
answer is C.
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Detailed Solution
When 20 ml of NaOH is added, equivalents point is reached.Equivalents of HCl = Equivalents of NaOH25 x 10-3 x M = 10-1 x 20 x 10-3M=2025×10=0.08M
25 mL of HCl solution is titrated with 0.10 mole L–1 NaOH solution in a conductivity cell. The data obtained were plotted to give the graph shown belowThe concentration of HCl solution is