Q.

25 mL of HCl solution is titrated with 0.10 mole L–1 NaOH solution in a conductivity cell. The data obtained were plotted to give the graph shown belowThe concentration of HCl solution is

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0.040 M

0.060 M

0.080 M

0.01 M

answer is C.

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Detailed Solution

When 20 ml of NaOH is added, equivalents point is reached.Equivalents of HCl = Equivalents of NaOH25 x 10-3 x M = 10-1 x 20 x 10-3M=2025×10=0.08M

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