180ml of hydrocarbon having the molecular weight 16, diffuses in 1.5 min. Under similar conditions time taken by 120ml of SO2 to diffuse is

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2 min

1.5 min

1 min

1.75 min

answer is A.

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Detailed Solution

Vt∝1MVHC×tSO2tHC×VSO2=MSO2MHC180×tSO21.5×120=6416tSO2=2 min

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