Q.

10 mL of liquid carbon disulphide (specific gravity 2.63) is burnt in oxygen. Find the volume of the resulting gases measured at STP.

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a

23.25 L

b

23.50 L

c

22.26 L

d

20.08 L

answer is A.

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Detailed Solution

CS2 + 3O2 →  CO2 + 2SO2Volume of CS2 = 10mldensity of CS2 = 2.63g/mlWeight of CS2 = 2.63(10) = 26.3gCS2 + 3O2 →  CO2 + 2SO2  76g               22.4l    (2 x 224l)   26.3g            'X1l'        'X2'lX1 =26.376×22.4 =7.75 l X2 =26.376×2×22.4 =15.5lTotal volume of gases liberated STP  = (15.5 + 7.75) lit                                                     = 23.25 lit
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10 mL of liquid carbon disulphide (specific gravity 2.63) is burnt in oxygen. Find the volume of the resulting gases measured at STP.