10 mL of 1 M BaCl2 solution and 5 mL 0.5 M K2SO4 are mixed together to precipitate out BaSO4. The amount of BaSO4 precipitated will be

BaCl2+    K2SO4⟶BaSO4↓+2KCl10×1         5×0.5=10mmol    =2.5mmolHere, K2SO4 is the limiting reagent1 mmol K2SO4 ≡ 1 mmol BaSO42.5 mmol K2SO4 ≡ 2.5 mmol BaSO4≡2.51000=0.0025 mol BasO4