$$100$$ ml of $$0.2$$ M $$H2SO4$$ is added to $$100$$ ml of $$0.2$$ M NaOH. The resulting solution will be

Question

$$100$$ ml of $$0.2$$ M $$H2SO4$$ is added to $$100$$ ml of $$0.2$$ M NaOH. The resulting solution will be

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Meq of $$0.2$$ M $$H2SO4$$ $$=$$ $$2$$ × $$0.2$$ $$M1000$$ × $$100$$ $$=$$ $$0.04$$ $$meq/LMeq$$ of $$.2$$ M NaOH $$=$$  $$0.2$$ $$1000$$ × $$100$$ $$=$$ $$0.02$$ meq.$$/L$$                  $$H+$$ left unreacted $$=$$ $$0.04$$ $$-0.02=0.02Total$$ volume $$=$$ $$200$$ ;  [$$H+$$] $$=$$ $$0.02200$$ $$=$$ $$.0001=10-4MpH$$ $$=-log$$ [$$H+$$]  $$=$$ $$4$$.Another method:                           Strength of $$H2SO4$$ $$=VANA=100$$×$$0.4$$ $$=40$$ (Since$$ $$NA=2$$×$$M)                           Strength of NaOH $$=VBNB$$ $$=100$$×$$0.2=20$$      ∴ VANA > VBNB  and the resultant solution is acidic.

100 ml of 0.2 M $H_{2} {SO}_{4}$ is added to 100 ml of 0.2 M NaOH. The resulting solution will be

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100 ml of 0.2 M H2SO4 is added to 100 ml of 0.2 M NaOH. The resulting solution will be

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100 ml of 0.2 M $H_{2} {SO}_{4}$ is added to 100 ml of 0.2 M NaOH. The resulting solution will be