100 ml of 0.2 M H2SO4 is added to 100 ml of 0.2 M NaOH. The resulting solution will be

Meq of 0.2 M H2SO4 = 2 × 0.2 M1000 × 100 = 0.04 meq/LMeq of .2 M NaOH =  0.2 1000 × 100 = 0.02 meq./L                  H+ left unreacted = 0.04 -0.02=0.02Total volume = 200 ;  [H+] = 0.02200 = .0001=10-4MpH =-log [H+]  = 4.Another method:                           Strength of H2SO4 =VANA=100×0.4 =40 (Since NA=2×M)                           Strength of NaOH =VBNB =100×0.2=20      ∴ VANA > VBNB  and the resultant solution is acidic.