First slide

Concentration methods

Question

800 ml of 1 M HCl and 200 ml of 2 M NaOH are mixed with each other. Normality of the resultant mixture is ----- N

Moderate

A

0.4
B

0.7
C

0.5
D

0.6

Solution

$V_{a} N_{a} = 800 (1) 1; V_{b} N_{b} = 200 (2) 1; V_{a} N_{a} > V_{b} N_{b}; N = {[H]}^{+} = \frac{V_{a} N_{a} - V_{b} N_{b}}{Total volume of the mixture}; N = {[H]}^{+} = \frac{800 - 400}{1000} N = 0.4 N;$

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