First slide

Concentration methods

Question

300 ml of 3 M HCl and 200 ml of 1 M NaOH are mixed with each other. Proton concentration of the resultant mixture is ----- M

Moderate

A

1.4
B

1.2
C

1.5
D

1.6

Solution

$V_{a} N_{a} = 300 (3) 1; V_{b} N_{b} = 200 (1) 1; V_{a} N_{a} > V_{b} N_{b}; N = {[H]}^{+} = \frac{V_{a} N_{a} - V_{b} N_{b}}{Total volume of the mixture}; N = {[H]}^{+} = \frac{900 - 200}{500} N = 1.4 N;$

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