10 ml of 0.1 M HCl solution is diluted to 1000 ml solution. Proton concentration of the solution will be

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10-3 M

5×10-4 M

2×10-3 M

4×10-4 M

answer is A.

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Detailed Solution

Dilution law :V1N1=V2N2 10(0.1)1=1000×N2 N2=10-3N; [H+]=Normality of strog acid ∴[H+]=10-3 M

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