20 ml of 0.02 M KMnO4 was required to completely oxidise 10 ml of oxalic acid solution. What is the molarity of the oxalic acid solution?

The concerned reaction is 2KMnO4+3H2SO4+5(COOH)2→K2SO4+2MnSO4+10CO2+8H2O[For KMnO4]                         [For oxalic acid]V1=20ml                              V2=10mlM1=0.02M                           M2=?n1=2,                          n2=5M1V1n1=M2V2n20.02×202=M2×105M2=0.02×20×510×2=0.1M