50 mL of 1M oxalic acid (molar mass = 126 g mol-1) is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. Amount of oxalic acid in grams adsorbed per gram of the charcoal is
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a
3.15
b
1.575
c
6.30
d
12.60
answer is C.
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Detailed Solution
50 mL of 1 M oxalic acid = 50 × 1millimo50 mL of 0.5 M oxalic acid = 50 × 0.5 millimolThus, oxalic acid adsorbed = 50(1- 0.5)=50×0.5 millimol =50×0.51000mol=50×0.51000×126g=3.15gCharcoal = 0.5g Thus, oxalic acid adsorbed per gram of charcoal =3.150.5=6.3