Q.

100 ml of 0.025M solution of chloride of ‘X’ required 200 ml of 0.05M solution of AgNO3 for complete precipitation. Formula of the chloride salt is

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answer is 3.

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Detailed Solution

Millimoles of Cl- solution = 100(0.025) = 2.5Millimoles of  AgNO3solution = 200(0.05) = 10            Millimoles of  AgNO3 = ‘4’ times millimoles of chloride solution.∴  Formula of the salt =  XCl4XCl4+4AgNO3→ 4AgCl+XNO34
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100 ml of 0.025M solution of chloride of ‘X’ required 200 ml of 0.05M solution of AgNO3 for complete precipitation. Formula of the chloride salt is