100 mL 0.01M solution of complex compound Ir Br35NH3 was treated with excess AgNO3 solution and precipitate of AgBr was obtained, then number of moles of AgBr obtained is
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a
0.01
b
0.001
c
0.02
d
0.002
answer is D.
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Detailed Solution
IrNH35BrBr21 millimole of the complex compound [Ir(NH3)5Br]Br2 was treated with excess AgNO3 to give 2 millimoles of AgBr (0.002 moles).
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100 mL 0.01M solution of complex compound Ir Br35NH3 was treated with excess AgNO3 solution and precipitate of AgBr was obtained, then number of moles of AgBr obtained is