40 mL of 0.025 M solution of the protonated form of the amino acid phenyl alanine (H2A+ ) is treated with 10 mL of 0.1 M NaOH. pH at this stage ispKa1=1.82,pKa2=9.13 of H2A+

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5.48

7.00

1.82

9.13

answer is A.

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Detailed Solution

For amphiprotic salt,pH=pKa1+pKa22=1.82+9.132=5.48

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