25 ml of a 0.1 (M) solution of a stable cation of transition metal z reacts exactly with 25 ml of 0.04 (M) acidified KMnO4 solution. Which of the following is most likely to represent the change in oxidation state of Z correctly ?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Z+→ Z2+
b
Z2+→ Z3+
c
Z3+→ Z4+
d
Z2+→ Z4+
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
(VM×n-factor)Z = (VM×n-factor)KMnO425 x 0.1 x n-factor = 25 x 0.04 x 5n-factor = 25× 0.04 × 525 × 0.1 = 2which is possible in (d) option