Q.

450 ml of 0.9 M Sulphuric acid is diluted to 0.45 N solution. Volume of water added is ------ mL

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a

450

b

1800

c

1350

d

900

answer is C.

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Detailed Solution

V1N1=V2N2   4500.92=V20.45 ;             V2=1800 ml ;      Vwater =V2-V1=1350 ml ;
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450 ml of 0.9 M Sulphuric acid is diluted to 0.45 N solution. Volume of water added is ------ mL