200 ml of 2 M Sulphuric acid is diluted to 0.4 N solution. Volume of water added is ------ mL

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2000

1800

800

1000

answer is B.

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Detailed Solution

V1N1=V2N2 20022=V20.4 ; V2=2000 ml ; Vwater =V2-V1=1800 ml ;

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