50 ml of 2.5 M Sulphuric acid is diluted to 0.5 N solution. Volume of water added is ------ mL

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500

400

450

150

answer is C.

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Detailed Solution

V1N1=V2N2 502.52=V20.5 ; V2=500 ml ; Vwater =V2-V1= 450 ml ;

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