30ml of a mixture of CH4 and C2H4 were burnt in excess of air. The volume of CO2 produced after explosion and cooling was 40ml. The composition of CH4 in the mixture is

Volume of gaseous mixture of CH4 and C2H4         = 30mlVolume of CO2 liberated due to the combustion mixture   = 40mlLet the volume of C2H4  in the mixture be V ml then the Volume of CH4 in the mixture will be (30-V)mlA) C2H4 + 3 O2 →2 CO2 + 2H2O(l) From stoichiometry, CO2 obtained from “V” ml of Ethene = 2V mlCH4 + 2 O2 →CO2 + 2H2O(l)From stoichiometry, CO2 obtained from (30 - V) ml of methane = (30 - V) mlTotal volume of CO2 formed = 2V+(30-V) = (30 + V)Given 30 + V = 40                 V = 10ml