Q.

20 ml of a mixture of CO and H2 were mixed with excess of O2 and exploded and cooled. There was a volume contraction of 18 mL. All volume measurements corresponds to room temperature (27°C) and one atmospheric pressure. Determine the volume ratioV1:V2 of CO and H2 in the original mixture.

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a

1:2

b

3 : 2

c

2:3

d

4 : 1

answer is B.

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Detailed Solution

COx+12O2x/2⟶CO2x H2(20−x)+12O220−x2⟶H2O(l);     Volume contraction= V.R-V.P=(x+x2-x)+[20-x+12(20-x)-0]  18=x2+3(20-x)2x=12mL=COH2=8mLVCO:VH2=12:8=3:2
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