56 mL of N2 gas at N. T.P. weighs 0.07 g. Calculate the atomic weight of nitrogen

We know 22400 mL of any gas at N. T.P. weighs equal to its g. mol. wt. So, we have: 56 mL of  N2 weighs = 0.07 g ∴22400mL of N2 weighs=0.0756×22400=28gSince 1 mole of N2  consists of  2 mol atoms of nitrogeng. at. wt. of nitrogen =282=14g∴at. wt. of nitrogen= 14.