10 mL of 0.2N HCI and 30 mL of 0.1 N HCI together exactly neutralise 40 mL of solution of NaOH, which is also exactly neutralised by a solution in water of 0.61 g of an organic acid. What is the equivalent weight of the organic acid?
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a
61
b
91.5
c
122
d
183
answer is C.
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Detailed Solution
10 mL of 0.2 N HCI + 30 mL of 0.1N HCI = 40 mL of NaOH (≡0.61g of organic acid)mEq of HCI ≡ mEq of NaOH ≡ mEq of organic acid 10×0.2+30×0.1≡0.61E×10005=0.61×1000EE=6105=122