Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

500 mL of 0.1 N solution of iodine contains 6.35 g. Calculate the equivalent weight of iodine.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 127.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

500mL=0.5L ,0.5L I2=6.35g. So,1L I2=6.350.5=12.7gL−Thus, eq. wt. =12.70.1=127.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
500 mL of 0.1 N solution of iodine contains 6.35 g. Calculate the equivalent weight of iodine.