250 mL of a Na2CO3 solution contains 2.65 g of Na2CO3. 10 mL of this solution is added to X mL of water to obtain 0.001 M Na2CO3 solution. The value of X is:(Molecular mass of Na2CO3 = 106amu)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

1000

990

9990

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Molarity of solution M=wB×1000mB×V=2.65×1000106×250=0.1M1V1=M2V20.1×10=0.001(10+x)x=990 mL

Watch 3-min video & get full concept clarity