500 ml of nitrogen at 27°C is cooled to-5°C at the same pressure. The new volume becomes

Given initial volume (V1)= 500 mL; Initial temperature T1=27∘C=300K and final temperature T2=−5∘C=268 K.From Charle's law:V1T1=V2T2 or 500300=V2268Where V2= New volume of gasV2=500300×268=446.66 mL