112ml. of oxygen at STP is subjected to liquefication. The mass of liquid oxygen obtained is

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0.64 g

0.16 g

0.32 g

0.96 g

answer is B.

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Detailed Solution

moles of O2=0.112294=0.005According to Law of mass conservation :Mass of liquid Oxygen obtained = number of moles x GMW of O2 = 0.005 x 32 =0.16 gm.

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