100ml of a sample of water requires 0.98mg of K2Cr2O7 (M.W. = 294) in presence of the H2SO4 for the oxidation of dissolved organic matter in it. The COD of the water sample is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

COD=wt of K2Cr2O7gm×8×10649×volume of sampleml COD=0.98×10-3×8×10649×100=1.6 ppm

Watch 3-min video & get full concept clarity