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100ml of a sample of water requires 0.98mg of K2Cr2O7 (M.W. = 294) in presence of the H2SO4 for the oxidation of dissolved organic matter in it. The COD of the water sample is

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answer is 2.

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Detailed Solution

COD=wt of K2Cr2O7gm×8×10649×volume of sampleml COD=0.98×10-3×8×10649×100=1.6 ppm

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