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Q.

250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3. If 10 ml of this solution is diluted to one litre. what is the concentration of the resultant solution (mol.wt. of Na2CO3=106)

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a

0.1 m

b

0.001 m

c

0.01 m

d

10-4 m

answer is B.

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Detailed Solution

Molarity =W(gm)×1000 molecularwt. ×V(ml.)=2.65×1000106×250=0.1M10ml of this solution is diluted to 1000mlM1V1=M2V210×0.1=1000×xx=0.1×101000=0.001M.
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