50 mL of a solution containing 1 g each of Na2CO3, NaHCO3 and NaOH was titrated with N-HCl. What will be the titre reading when only phenolphthalein is used as indicator ?
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a
35 mL
b
32.5 mL
c
24.5 mL
d
34.4 mL
answer is D.
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Detailed Solution
At the end point using phenolphthalein as indicator uses complete NaOH and 12 Meq. of Na2CO3.∴ Meq. of NaOH+12 Meq. of Na2CO3=Meq. of HCl140 × 1000 +12 × 1106 × 2× 1000=V ×1∴ V=34.4 ml