20 ml solution containing mixture of NaOH and Na2CO3 require 60 ml of 0.5 N H2SO4 for the end point using phenolphthalein as indicator. After this when same solution was titrated using methyl orange indicator. A further 20 ml of 0.5 N H2SO4 was needed for the second end point. Calculate the molarity of NaOH.

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answer is 1.00.

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Detailed Solution

eNaOH=eNaOH+eNa2CO3 601000×12=n1+n2 n1+n2=30×10−3 eNaHCO3=eH2SO4 n2=nNa2CO3×1=201000×12=10×10−3 n1=20×10−3 NaOH=20×10−320×10−3=1 M= 1.00

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