A 50 ml solution of pH = 1 is mixed with a 50 ml solution of pH = 2. The pH of the mixture will be nearly

pH = 1 means H+ = 10-1 M. PH=2 means  H+ = 10-2 M.  After mixing  : (M V)mix =M1V1+M2V2 (M ×100)mix =(10-1×50) +(10-2×50)                            =5+0.5   Mmix  or [H+ ]  =5.5100=5.5×10-2 PH =-log [H+] = -log 5.5 × 10-2  pH = 2 - log 5.5 = 2-0.74=1.26