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100 mL of a water sample contains 0.81 g of calcium bicrabonate and 0.73 g of magnesium bicarbonate. If The hardness of this water sample expressed in terms of equivalents of CaCO3 is 10X ppm then 'X' is (Molar mass of calcium bicarbonate is 162 g mol–1 and magnesium bicarbonate is 146 g mol–1)

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answer is 4.

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Detailed Solution

Here hardness of water is expressed in terms of CaCO3.∴ Equivalent of CaCO3 = Equivalent of Ca(HCO3)2 + Equivalent of Mg(HCO3)2⇒ 2 × W100 = 0.81162×2+0.73146×2⇒ W = 1 gmVolume of water = 100 mL∴ Mass of water = 100 g∴ Hardness = 1.0100×106 = 10000 ppm= 104ppm

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