A 25.0 mm x 40.0 mm piece of gold foil is 0.25 mm thick. The density of gold is 19.32 g/cm3.How many gold atoms are in the sheet ? (Atomic weight : Au=197.0)

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7.7 x 1023

1.5 x 1023

4.3 x 1021

1.47 x 1022

answer is D.

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Detailed Solution

Volume of gold foil = 25 x 40 x 0.25 mm3= 250 x10-3cm3Mass of gold foil = 19.32 x 250 x10-3 g= 4.83 gNo. of gold atoms = =4.83197×NA=1.47 x 1022

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