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Q.

MnO4−+8H++5e−→Mn2++4H2OIf H+ concentration is decreased from 1 M to 10-4 M at 25oC,

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a

the potential decreases by 0.38 V with decrease in oxidising power

b

the potential increases by 0.38 V with increase in oxidising power

c

the potential decreases by 0.25 V with decrease in oxidising power

d

the potential decreases by 0.38 V without affecting oxidising power

answer is A.

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Detailed Solution

E1=Eo-0.05915logMn+2H+8 E2=Eo-0.05915logMn+210-48 E2-E1=0.05915log10-48       ∆E=-0.378≃ -0.38
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