Q.
1 mol benzene (P°benzene = 42 mm) and 2 mol toluene (P°toulene = 36 mm) will have
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a
Total vapour pressure of 38 mm.
b
Mole fraction of vapour of benzene above liquid mixture is 7/19
c
Positive deviation from Raoult's law.
d
Negative deviation from Raoult's law.
answer is A.
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Detailed Solution
Benzene and toluene⇒ Ideal solution. PTotal=P°AXA+P°BXB=42×13+36×23=38 mm Hg XVBenzene=PBenzenePTotal=42×1338=719
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