1 mol benzene (P°benzene = 42 mm) and 2 mol toluene (P°toulene = 36 mm) will have

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Total vapour pressure of 38 mm.

Mole fraction of vapour of benzene above liquid mixture is 7/19

Positive deviation from Raoult's law.

Negative deviation from Raoult's law.

answer is A.

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Detailed Solution

Benzene and toluene⇒ Ideal solution. PTotal=P°AXA+P°BXB=42×13+36×23=38 mm Hg XVBenzene=PBenzenePTotal=42×1338=719

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